One ride has a 2 34 of an hour wait. However, you have a fast pass that will save you 1 12 hours of wait time. How long will you have to wait to get on the ride?(2 points) Responses 1 14 hours 1 14 hours 3 14 hours 3 14 hours 1 23 hours 1 23 hours 14 hours

1 answer

To find out how long you'll have to wait for the ride with your fast pass, first convert the wait times into improper fractions.

The original wait time is \( 2 \frac{3}{4} \) hours. Converting that to an improper fraction:

  • \( 2 \) hours is \( 2 \times 4 = 8 \) quarters of an hour.
  • Adding \( 3 \) quarters gives \( 8 + 3 = 11 \) quarters. So, \( 2 \frac{3}{4} \) hours is \( \frac{11}{4} \) hours.

Now, the fast pass saves \( 1 \frac{1}{2} \) hours, which in fractions is:

  • \( 1 \) hour is \( 1 \times 2 = 2 \) halves of an hour.
  • Adding \( 1 \) half gives \( 2 + 1 = 3 \) halves. So, \( 1 \frac{1}{2} \) hours is \( \frac{3}{2} \) hours.

Now, we will subtract the saved time from the original wait time. First, we need a common denominator for the fractions \( \frac{11}{4} \) and \( \frac{3}{2} \):

  • The least common denominator is \( 4 \).

Convert \( \frac{3}{2} \) to quarters:

  • \( \frac{3}{2} = \frac{3 \times 2}{2 \times 2} = \frac{6}{4} \).

Now, subtract the two fractions: \[ \frac{11}{4} - \frac{6}{4} = \frac{5}{4} \]

Finally, convert \( \frac{5}{4} \) back to a mixed number:

  • \( \frac{5}{4} = 1 \frac{1}{4} \).

So, after using the fast pass, you'll have to wait 1 hour and 15 minutes, or 1 1/4 hours.

Among the options provided, the correct answer is: 1 1/4 hours.