One positive integer is three moee than twice another and their sum is greater than 65 but less than 75. What pairs of integers satisfy this conditions?

Answer 1

one number --- x
the other ----- 2x+3

their sum = 3x+3

65 < 3x+3 < 75
subtract 3
62 < 3x < 72
divide by 3
62/3 < x < 24
but x is to be an integer, so the next integer after 62/3 is 21
21 ≤ x < 24

so the only numbers possible are
21, 22, and 23

as pairs that would be
(21,45)
(22,47)
(23,49