If x=-4 is one of the solutions, then x+4 must be a factor of x^3 - 28x - 48
so do a long division. You must get a quadratic with no remainder.
solve that quadratic = 0 to get the other two zeros.
hint: the remaining quadratic factors to give 2 more integer solutions.
One of the zeros of the function f(x)=x^3-28x-48 is x=-4. Factor the function. Show your work.
How do I solve this?? Please help??
1 answer
1 answer