One of the two equal angles of an isosceles.triangle is greatest than the third angle 18° . Find the three angles of the isosceles triangle

Answer 1

A = greatest angle

B = smaller angle

A = B + 18°

The sum of the angles in a triangle is 180°

2 A + B = 180°

2 ( B + 18° ) + B = 180°

2 B + 2 * 18° + B = 180°

3 B + 36° = 180° Subtract 36° to both sides

3 B + 36° = 180°

3 B + 36° - 36 ° = 180° - 36°

3 B = 144° Divide both sides by 3

B = 144° / 3

B = 48°

A = B + 18°

A = 48° + 18°

A = 66°

Three angles of the triangle:

66° , 66° , 48°