There are easier ways to do this but I think this is the best way to go about it. I would change the kg to grams.
mols Fe = grams Fe/atomic mass Fe = ?
Using the coefficients in the balanced equation, convert mols Fe to mols Fe2O3. That is mols Fe x (1 mol Fe2O3/2 mols Fe) = ?
Now convert mols Fe2O3 to grams Fe2O3.
g Fe2O3 = mols Fe2O3 x molar mass Fe2O3 = ?
Finally, %Fe2O3 = %purity = (g Fe2O3/
%Fe = (mass Fe/mass sample)*100 = ?
Substitute and solve for %Fe which is the percent purity.
One of the reactions that occurs in a blast furnace, in which iron ore is converted to cast iron, is
Fe2O3 + 3CO → 2Fe + 3CO2
Suppose that 1.59 × 103 kg of Fe is obtained from a 2.54 × 103 kg sample of Fe2O3. Assuming that the reaction goes to completion, what is the percent purity of Fe2O3 in the original sample?
2 answers
Can you put the figures into the equation for me, because I do not quite understand this?
1 answer