One of the legs of a right triangle measures 10 cm and the other leg measures 7 cm. Find the measure of the hypotenuse. If necessary, round to the nearest tenth.
3 answers
Using the Pythagorean theorem, we have $c^2 = a^2 + b^2 = 10^2 + 7^2 = 100 + 49 = 149.$ Taking the square root of both sides, we find $c = \sqrt{149} \approx \boxed{12.2}$ cm.
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Using the Pythagorean theorem $a^2 + b^2 = c^2$, where $a$ and $b$ are the legs of the right triangle and $c$ is the hypotenuse, we can plug in the lengths of the legs:
$10^2 + 7^2 = c^2$
$100 + 49 = c^2$
$149 = c^2$
Taking the square root of both sides, we get:
$c = \sqrt{149} \approx 12.2$
Therefore, the length of the hypotenuse is approximately $\boxed{12.2}$ cm.
Using the Pythagorean theorem $a^2 + b^2 = c^2$, where $a$ and $b$ are the legs of the right triangle and $c$ is the hypotenuse, we can plug in the lengths of the legs:
$10^2 + 7^2 = c^2$
$100 + 49 = c^2$
$149 = c^2$
Taking the square root of both sides, we get:
$c = \sqrt{149} \approx 12.2$
Therefore, the length of the hypotenuse is approximately $\boxed{12.2}$ cm.