Asked by Luma
One of the fastest recorded pitches in major-league baseball, thrown by Nolan Ryan in 1974, was clocked at 96.8 mi/h.
The acceleration of gravity is 32 ft/s^.
If a pitch were thrown horizontally witha velocity of 96.8 mi/h, how far would the ball fall vertically by the time it reached home plate, 60 ft away? Answer in units of ft.
The acceleration of gravity is 32 ft/s^.
If a pitch were thrown horizontally witha velocity of 96.8 mi/h, how far would the ball fall vertically by the time it reached home plate, 60 ft away? Answer in units of ft.
Answers
Answered by
Henry
Xo = 96.8 mi/h * 5280Ft/mi * 1h/3600s =
142 Ft/s.
Dx = Xo*Tf = 60 Ft.
142Ft/s * Tf = 60.
Tf = 0.423 s. = Fall time.
d = 0.5g*Tf^2 = 16*0.423^2 = 2.86 Ft.,
Vertically.
142 Ft/s.
Dx = Xo*Tf = 60 Ft.
142Ft/s * Tf = 60.
Tf = 0.423 s. = Fall time.
d = 0.5g*Tf^2 = 16*0.423^2 = 2.86 Ft.,
Vertically.
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