One molecule of Iodine (I2) and two molecules of sodium chloride (NaCl) combine in a reaction. How many atoms are in the products?

Question

a
6
b
2
c
3
d
4

Answer 1

In the reaction between one molecule of Iodine (I₂) and two molecules of Sodium Chloride (NaCl), we need to analyze the number of atoms in the products.

1. Molecule of Iodine (I₂): Contains 2 iodine atoms.
2. Molecules of Sodium Chloride (NaCl): Each NaCl molecule contains 1 sodium atom and 1 chlorine atom. Since there are 2 NaCl molecules:
   • Sodium atoms from 2 NaCl = 2 Na
   • Chlorine atoms from 2 NaCl = 2 Cl

Now, let's total up the atoms:

• Iodine atoms from I₂ = 2
• Sodium atoms from 2 NaCl = 2
• Chlorine atoms from 2 NaCl = 2

Adding these together:

• Total atoms = 2 (I) + 2 (Na) + 2 (Cl) = 6 atoms

Thus, the number of atoms in the products is 6.

The correct answer is a. 6.