To determine how many atoms are in the products of the reaction between bromine (Br₂) and potassium chloride (KCl), we need to consider the reaction itself.
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Molecules involved:
- 1 molecule of bromine (Br₂) contains 2 bromine atoms.
- 2 molecules of potassium chloride (KCl) contain 2 potassium atoms (K) and 2 chloride atoms (Cl).
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Total count before the reaction:
- From Br₂: 2 Br atoms
- From 2 KCl: 2 K atoms + 2 Cl atoms = 4 atoms
So, the total number of atoms before the reaction is:
- 2 (from Br₂) + 2 (from KCl) + 2 (from KCl) = 6 atoms.
- Products: In the course of the reaction, bromine typically reacts with potassium chloride to form potassium bromide (KBr). Each KCl will provide K for the Br, leading to the formation of:
- 2 molecules of KBr, which will contain:
- 2 K atoms and 2 Br atoms.
- Total atoms in the products:
- From 2 KBr: 2 K atoms + 2 Br atoms = 4 atoms.
Thus, the total number of atoms in the products is 4.
Therefore, the answer is four.