One molecule of bromine (Brz) and two molecules of potassium chloride (KCI) combine in a reaction. How many atoms are in the products? (1 point)

• six
• four
O two
• three

1 answer

To determine how many atoms are in the products of the reaction between bromine (Br₂) and potassium chloride (KCl), we need to consider the reaction itself.

  1. Molecules involved:

    • 1 molecule of bromine (Br₂) contains 2 bromine atoms.
    • 2 molecules of potassium chloride (KCl) contain 2 potassium atoms (K) and 2 chloride atoms (Cl).
  2. Total count before the reaction:

    • From Br₂: 2 Br atoms
    • From 2 KCl: 2 K atoms + 2 Cl atoms = 4 atoms

So, the total number of atoms before the reaction is:

  • 2 (from Br₂) + 2 (from KCl) + 2 (from KCl) = 6 atoms.
  1. Products: In the course of the reaction, bromine typically reacts with potassium chloride to form potassium bromide (KBr). Each KCl will provide K for the Br, leading to the formation of:
  • 2 molecules of KBr, which will contain:
    • 2 K atoms and 2 Br atoms.
  1. Total atoms in the products:
  • From 2 KBr: 2 K atoms + 2 Br atoms = 4 atoms.

Thus, the total number of atoms in the products is 4.

Therefore, the answer is four.