One molecule of bromine (BR2) and two molecules of potassium chloride (KCI) combine in a reaction. How many atoms are in the products?

Answer 1

In the reaction, one molecule of bromine (Br2) and two molecules of potassium chloride (KCI) combine.

The chemical equation for this reaction is:

Br2 + 2KCI -> 2KBr + Cl2

From the balanced chemical equation, we can see that 2 moles of potassium bromide (KBr) and 1 mole of chlorine gas (Cl2) are produced.

Since each mole of a substance contains Avogadro's number (6.022 x 10^23) of atoms or molecules, we can determine the number of atoms in the products.

For potassium bromide (KBr), 2 moles of KBr contain 2 x Avogadro's number of atoms.

For chlorine gas (Cl2), 1 mole of Cl2 contains 2 x Avogadro's number of atoms.

Therefore, the total number of atoms in the products is (2 x Avogadro's number) + (2 x Avogadro's number) = 4 x Avogadro's number.

So, there are 4 x Avogadro's number (approximately 2.408 x 10^24) atoms in the products.