To determine the number of atoms in the products of the reaction between bromine (Br₂) and potassium chloride (KCl), we must first consider the reactants and how they combine.
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The given molecules:
- 1 molecule of bromine (Br₂) contains 2 bromine atoms.
- 2 molecules of potassium chloride (KCl) each contain 1 potassium atom and 1 chlorine atom. So, 2 molecules of KCl contain:
- 2 potassium (K) atoms
- 2 chlorine (Cl) atoms
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Combining these, we can summarize the total atoms from the reactants:
- From Br₂: 2 Br atoms
- From 2 KCl: 2 K atoms + 2 Cl atoms
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Now, let's add these up:
- Total Br atoms = 2
- Total K atoms = 2
- Total Cl atoms = 2
- Total = 2 Br + 2 K + 2 Cl = 6 atoms
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The likely reaction involving these reactants could be: \[ Br_2 + 2 KCl \rightarrow 2 KBr + Cl_2 \] In this reaction, potassium bromide (KBr) and chlorine gas (Cl₂) are formed.
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In the products:
- 2 molecules of KBr contain:
- 2 K atoms
- 2 Br atoms
- 1 molecule of Cl₂ contains:
- 2 Cl atoms
- 2 molecules of KBr contain:
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Therefore, the total number of atoms in the products is:
- Total K = 2
- Total Br = 2
- Total Cl = 2
- Total = 2 K + 2 Br + 2 Cl = 6 atoms
Thus, there are 6 atoms in the products.