One molecule if bromine (Br2) and two molecule if potassium chloride (KCI) combine in a reaction. How many atoms are in the products?

Answer 1

To determine the number of atoms in the products of the reaction between bromine (Br₂) and potassium chloride (KCl), we must first consider the reactants and how they combine.

1. The given molecules:

   • 1 molecule of bromine (Br₂) contains 2 bromine atoms.
   • 2 molecules of potassium chloride (KCl) each contain 1 potassium atom and 1 chlorine atom. So, 2 molecules of KCl contain:
     • 2 potassium (K) atoms
     • 2 chlorine (Cl) atoms

2. Combining these, we can summarize the total atoms from the reactants:

   • From Br₂: 2 Br atoms
   • From 2 KCl: 2 K atoms + 2 Cl atoms

3. Now, let's add these up:

   • Total Br atoms = 2
   • Total K atoms = 2
   • Total Cl atoms = 2
   • Total = 2 Br + 2 K + 2 Cl = 6 atoms

4. The likely reaction involving these reactants could be: \[ Br_2 + 2 KCl \rightarrow 2 KBr + Cl_2 \] In this reaction, potassium bromide (KBr) and chlorine gas (Cl₂) are formed.

5. In the products:

   • 2 molecules of KBr contain:
     • 2 K atoms
     • 2 Br atoms
   • 1 molecule of Cl₂ contains:
     • 2 Cl atoms

6. Therefore, the total number of atoms in the products is:

   • Total K = 2
   • Total Br = 2
   • Total Cl = 2
   • Total = 2 K + 2 Br + 2 Cl = 6 atoms

Thus, there are 6 atoms in the products.