One mole of an ideal gas initially at a temperature of Ti = 7.4°C undergoes an expansion at a constant pressure of 1.00 atm to eight times its original volume.

Question

One mole of an ideal gas initially at a temperature of Ti = 7.4°C undergoes an expansion at a constant pressure of 1.00 atm to eight times its original volume.
(a) Calculate the new temperature Tf of the gas.______J

(b) Calculate the work done on the gas during the expansion.________kJ

Hunter · Accepted Answer

Good response, just remember to have a negative sign in the work if asking for work done on the gas.

Elena · Answer

(a) Ti=273+7.4=280.4 K Vi/Ti = Vf/Tf Vi/280.4 =8 Vi/Tf Tf=8•280.4 = 2243.2 K b) p•ΔV=νRΔT ν =1 mol p•ΔV= RΔT W = p•ΔV= RΔT= = 8.31•(2243.2-280.4)= =1.63•10⁴ J =16.3 kJ

Ewin · Answer

Waw..Elena answer is so brilliant.. Thank you so much.. Hope can know you well