One mole (mol) of any substance consists of 6.022 x 10²³ molecules

(Avogadro's number). What is the translational kinetic energy of 12.00mol of
an ideal gas at 290.0K?

1 answer

https://www.softschools.com/formulas/physics/kinetic_energy_of_gas_formula/337/#:~:text=In%20an%20ideal%20gas%2C%20there,or%20vibration%20within%20the%20molecules.&text=using%20the%20formula%3A-,The%20average%20translational%20kinetic%20energy%20of%20a%20single%20molecule%20of,of%20molecules%20(Avogadro's%20number).
avg kinetic energy of ideal gas is 3/2 kT. k is Boltzman constant. T is in kelvin. This give you the avg KE per molecule. Multiply that by Avogadro's number x 12.
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