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One mole methane is completly burned in xcess oxygen. If 8.90x10^3kj of heat are given off from theis reaction, calculate the heat given off for 1.44g of methane.

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CH4 + 2O2 ==> CO2 + 2H2O
8.90 x 10^3 kJ given off for 1 mole(16 g) CH4.
1.44 g will give off
8.90 x 10^3 kJ x (1.44/16) = ??

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