One leg of a right triangle is 5 centimeters longer than the other leg. What quadratic inequality represents the length of the shorter leg, x, when the hypotenuse is at least 13 centimeters long?(1 point)

Responses

x2+(5x)2≥132
x squared plus 5 x squared is greater than or equal to 13 squared

x2+(x+5)2≥132
x squared plus open paren x plus 5 close paren squared is greater than or equal to 13 squared

x2+(5x)2≤132
x squared plus 5 x squared is less than or equal to 13 squared

x2+(x+5)2≤132

1 answer

To find the quadratic inequality that represents the length of the shorter leg \( x \), we first define the lengths of the legs of the right triangle.

Let:

  • The shorter leg be \( x \) cm.
  • The longer leg be \( x + 5 \) cm (since it is 5 cm longer than the shorter leg).

According to the Pythagorean theorem, the relationship between the lengths of the legs and the hypotenuse in a right triangle is given by:

\[ a^2 + b^2 = c^2 \]

Where:

  • \( a \) and \( b \) are the lengths of the legs,
  • \( c \) is the length of the hypotenuse.

In this case, we have:

\[ x^2 + (x + 5)^2 \geq 13^2 \]

Thus, we can expand and combine the expressions:

\[ x^2 + (x^2 + 10x + 25) \geq 169 \]

This simplifies to:

\[ 2x^2 + 10x + 25 \geq 169 \]

Rearranging gives:

\[ 2x^2 + 10x - 144 \geq 0 \]

Now, rearranging the terms, we rewrite this as:

\[ x^2 + 5x - 72 \geq 0 \]

However, the correct format of the inequality only represents the lengths derived from the Pythagorean theorem at a minimum hypotenuse of 13 cm.

Thus, the correct option that represents this inequality is:

\[ x^2 + (x + 5)^2 \geq 13^2 \]

So the correct choice is:

\( x^2 + (x + 5)^2 \geq 13^2 \)