Asked by Jessica

One integer is 4 more than a second integer. Three times the first integer when added to two times the second integer is less than 23. Determine the largest possible values of the two integers.
Answered by stephanie
9 divided by 66
Answered by PsyDAG
Let x = one integer and x + 4 = the second.

3x + 2(x+4) < 23

Solve for x and x+4.

I hope this helps. Thanks for asking.
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