One integer is 4 more than a second integer. Three times the first integer when added to two times the second integer is less than 23. Determine the largest possible values of the two integers.

Answer 1

9 divided by 66

Answer 2

Let x = one integer and x + 4 = the second.

3x + 2(x+4) < 23

Solve for x and x+4.

I hope this helps. Thanks for asking.