120 x specific heat ( 17.5 - 88) + 250 x 4.18 ( 17.5 - 16)=0
- 8460 x specific heat +1567.5 =0
specific heat:
=0.185 J/g°C
One hundred twenty grams of metal at 88 degree Celsius is poured into a 70 grams insulated cup contains 250 grams of water at 16 degree Celsius .The final temperature of the mixture is 17.5 degree C.Determine the specific heat capacity of the metal.
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