Prob(Andy, Briana, Cam)
= (1/100)(1/99)(1/98) = 1/970200
prob (those 3 win)
= 1/C(100,3)
= 1/161700
One hundred tickets are sold for a raffle. Three prizes are awarded.
What is the probability that Andy wins first prize, Brianna wins second, and Cam wins third?
What is the probability that Andy, Brianna, and Cam are the three winners (not necessarily in that order)?
2 answers
Thank you!!!!!!!