To find the relative frequency of students who participate in band among those who do not play a sport, we need data from the survey about the number of students who play band and the number of students who do not play a sport.
Assuming we had the following setup from the table (note: you will replace these values with your own from the table you've referred to):
- Total students = 100
- Students who participate in band (B)
- Students who play a sport (S)
- Students who do not play a sport (N)
From the data you provide, let’s assume:
- Number of students who do not play a sport = N
- Number of those who do participate in band = B_no_sport
The relative frequency is calculated using the formula: \[ \text{Relative Frequency} = \frac{\text{Number of students in band with no sport}}{\text{Total number of students who do not play a sport}} \]
Thus: \[ \text{Relative Frequency of Band participation among non-sport players} = \frac{B_{\text{no sport}}}{N} \]
Make sure to plug in the values from the table you have to get the correct answer.
Regarding your second question about the houses being similar, it appears you may be referencing the idea of similar figures, where the ratios of corresponding sides are equal. For two houses to be similar, the ratios of corresponding side lengths must be equal.
The pairs you provided are:
- (4, 2)
- (12, 6)
- (32, 26)
- (36, 18)
You can determine the ratios as follows:
- \( \frac{x}{y} = \frac{4}{2} = 2 \)
- \( \frac{x}{y} = \frac{12}{6} = 2 \)
- \( \frac{x}{y} = \frac{32}{26} \approx 1.23 \)
- \( \frac{x}{y} = \frac{36}{18} = 2 \)
The pairs of values (x, y) that result in equivalent ratios are:
- (4, 2)
- (12, 6)
- (36, 18)
Thus, pairs (4, 2), (12, 6), and (36, 18) would ensure that the two houses are similar as they maintain the same side ratio of 2. The pair (32, 26) does not maintain that ratio and therefore would not qualify for similarity.
If you seek a specific outcome or confirmation on your provided values, please provide exact numbers or clarify further!