To find Work
Use the Work = Pressure * delta Volume
Be sure everything is in SI units
1atm=1.013*10^5
1cm^3=1*10^-5m^3
I have no idea how to find the change in internal energy though sorry
One gram of water changes from liquid to solid at a constant pressure of one atmosphere and a constant temperature of 0°C. In the process, the volume changes from 0.90 cm3 to 1.10 cm3.
The work done by the water is .02J, but I'm not sure how to find the internal energy. I tried 0, but that was wrong.
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