The principle of a lever is that the product of the force applied to the long end of the lever (F1) and the distance from the fulcrum (d1) is the same as the product of the force applied to the short end of the lever (F2) and the distance from the fulcrum (d2). In other words, F1 x d1 = F2 x d2.
In this case, we can use the lever to reduce the force needed to lift the bag by increasing the distance over which the force is applied. The distance d1 is 2 meters (the distance from the fulcrum to the end of the lever where the force is applied), and the distance d2 is 1 meter (the distance from the fulcrum to the point where the bag is lifted). We know that the force needed to lift the bag directly is 1000 N, so we can use the lever to apply less force over a longer distance.
To find the force needed with the lever, we can rearrange the lever principle equation to solve for F2:
F2 = (F1 x d1) / d2
Plugging in the values we know:
F2 = (1000 N x 2 m) / 1 m
F2 = 2000 N
Therefore, the force needed with the lever is 2000 N, which is less than the force needed to lift the bag directly.
One end of the lever is pushed down 2 meters to lift a heavy bag up to a surface 1 meter off the ground. If it takes 1000 N of force to lift the bag directly, what amount of force is needed to lift it with the lever?
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1 answer