Asked by Abud
One-dimensional motion: v(t) = -(t+1) * sin(t^2 / 2)
how often does a particle following that function change direction in the open interval (0,3).
how often does a particle following that function change direction in the open interval (0,3).
Answers
Answered by
Abud
It's part of an FRQ. I've been working at it for a while, but I have not gotten a single definitive answer.
Answered by
Abud
I'm allowed to graph it using a graphing calculator, but I want to understand why it's once.
Answered by
oobleck
the particle changes direction when it stops and reverses. That is, when v(t) = 0
sin(t^2/2) = 0 when t^2/2 = kπ
That is, when t = √2π, √4π, ...
Only √2π is in the interval (0,3)
sin(t^2/2) = 0 when t^2/2 = kπ
That is, when t = √2π, √4π, ...
Only √2π is in the interval (0,3)
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.