One atom of sodium (Na) has a mass of 23 amu (atomic mass units). According to the Law of Conservation of Mass, if two atoms of sodium are present in the reactants of a chemical equation, how much will the sodium weigh in the products of the reaction?(1 point)

Responses

184 amu
184 amu

23 amu
23 amu

11.5 amu
11.5 amu

46 amu

1 answer

According to the Law of Conservation of Mass, mass cannot be created or destroyed in a chemical reaction. If two atoms of sodium are present in the reactants, each weighing 23 amu, the total mass of sodium will be:

2 atoms × 23 amu/atom = 46 amu

Therefore, the sodium will weigh 46 amu in the products of the reaction.

The correct answer is 46 amu.