yes, the final velocity is
∆x/∆t = 630km/12.6hr = 50 km/hr
So, the acceleration is ∆v/∆t:
(50km/hr)/(1/2 hr) = 100km/hr^2
You might want to put that into standard SI units of m/s^2.
Once all of the passengers aboard it a train leaves the station and it takes 30 minutes to reach its maximum velocity once at maximum velocity train travels the next 6.30×10^2 km for the next 12.6 hours what is the acceleration of the train leaving the station. Do we find the final velocity by using v=deltax/t first? What should I do after that?
2 answers
Jupiter has an Equatorial radius of sour 1.7x10^4 km and it's period of rotation is 9 hours and 50 minutes. Calculate the average speed (in m/s) of an Equatorial point during one period of jupiter's rotation. Is the velocity different than the speed? How do I even go about finding the average speed of the Equatorial point?
2 answers