The height of a trapezoid is the perpendicular distance between its two parallel sides. In this case, the two parallel sides are AB and CD, which are horizontal and have the same y-coordinate of -6 (point A) and 5 (point C), respectively. Therefore, the height of the trapezoid is the vertical distance between these two parallel sides, which is 5 - (-6) = 11 units.
Therefore, the answer is A. 11 units.
On the coordinate plane shown, points A(−5,−6), B(2,−6), C(8,5), and D(−7,5)
are plotted and connected with line segments to form a trapezoid.
A graph is shown in the xy-plane. The values on the x-axis ranges from negative 8 to 8 in increments of 2 and the values on the y-axis ranges from negative 8 to 8 in increments of 2. Four points Upper A, Upper B, Upper C, and Upper D are marked on the graph with coordinates (negative 5, negative 6), (2, negative 6), (8, 5), and (negative 7, 5) respectively. The four points are joined together to form a trapezium UpperWord ABCD.
What is the height of the trapezoid?
A.
11 units
B.
7 units
C.
15 units
D.
10 units
1 answer
1 answer