On his way off to college, Russell drags his bag 15.0 m from the door of his house to the car at a constant speed with a horizontal force of 95.0 N. How much work does Russell do to overcome the force of friction?

Answer 1

work=force*distance.
The work he did is the same as work done on friction.

Answer 2

but the answer in my book is 1430, and i got 1425

Answer 3

That's probably because of significant figures. 15.0 m and 95.0 N both have three significant figures. Therefore, the answer should also have three significant figures. 1425 rounded to three sigfigs is 1430.

Answer 4

thanks