On Friday in class, we learned that if you were to aim right at the bulls-eye, the arrow would fall under gravity and drop below the intended target. If you intend to hit a bulls-eye it is necessary that you aim slightly above it. Suppose the arrow speed is the same (70 m/s) and the target is 10 meters away. What launch angle, Θ, is needed so that the arrow hits the bulls-eye?

Question

V=70m/s

Answer 1

hf=hi+70sinTheta*t-4.9t^2
but horizontally
10=70cosTheta*t
in the horizontal equation
t= 10/70costheta
put that into the vertical first equation, and solve for theta.
hf=hi

Answer 2

while john is traveling along an interstate highway, he notice a 160-mile marker a he passes through town. later john passes another mile marker, 115.
what is the distance between town and john's current location? what is his current position?