On average, Tony the turtle completes a 15-foot course in 1 minute, and Antonio the turtle completes an 18-foot course in 1 minute. If Tony and Antonio both start at the same time and travel in the same direction, how far apart will the turtles be after 5 minutes?(1 point) Responses 90 feet 90 feet 165 feet 165 feet 15 feet 15 feet 75 feet

1 answer

First, we need to determine the speeds of Tony and Antonio the turtles.

Tony the turtle completes a 15-foot course in 1 minute, so his speed is: \[ \text{Speed of Tony} = \frac{15 \text{ feet}}{1 \text{ minute}} = 15 \text{ feet per minute} \]

Antonio the turtle completes an 18-foot course in 1 minute, so his speed is: \[ \text{Speed of Antonio} = \frac{18 \text{ feet}}{1 \text{ minute}} = 18 \text{ feet per minute} \]

Next, we calculate the distance each turtle travels in 5 minutes.

Distance traveled by Tony in 5 minutes: \[ \text{Distance}{Tony} = \text{Speed}{Tony} \times \text{Time} = 15 \text{ feet per minute} \times 5 \text{ minutes} = 75 \text{ feet} \]

Distance traveled by Antonio in 5 minutes: \[ \text{Distance}{Antonio} = \text{Speed}{Antonio} \times \text{Time} = 18 \text{ feet per minute} \times 5 \text{ minutes} = 90 \text{ feet} \]

Now, we find the distance apart after 5 minutes by subtracting the distance traveled by Tony from the distance traveled by Antonio: \[ \text{Distance apart} = \text{Distance}{Antonio} - \text{Distance}{Tony} = 90 \text{ feet} - 75 \text{ feet} = 15 \text{ feet} \]

Therefore, after 5 minutes, Tony and Antonio will be 15 feet apart.

The correct answer is 15 feet.