Fp = Mg*sin A = Force parallel to the
incline and acting downward. When the
angle is increased, Fp increases which
increases the acceleration: a = Fp/M.
Friction is assumed to be negligible.
The increase in acceleration results in
an increase in velocity: V = a*t.
On an inclined plane, how does a larger angle of inclination result in a faster speed?
I tried working this out by myself using different values for the angle of incline and the same weight - which was just 100N. I found that the frictional force was equal to the force acting down the slope each time. I thought that if those forces balanced each other, the object would be at rest, which obviously won't be happening on an incline.
I also have to use tan(theta) to find the co-efficent of friction.
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