let there b x par-3, y par-4, z par-5 holes. Then
x+y+z = 18
3x+4y+5z = 66
y = 2z
Now just solve for x,y,z
On an 18-hole golf course, there are par-3 holes, par-4 holes, and par-5 holes. A golfer who shoots par on every hole has a total of 66. There are twice as many par-4 holes as there are par-5 holes. How many of each type of hole are there on the golf course?
How many par-3 holes are there__?
How many par-4 holes are there__?
How many par-5 holes are there__?
2 answers
I'm not sure if I did this right, but I followed your formula, and got 9,6, and 3 as the answer. Is this correct?
1 answer