Let's represent the height of each snowman as a function of time \( t \) (in hours after sunrise).
Snowman A:
- Initial height: 33 inches
- Decrease rate: 2 inches per hour
The height of Snowman A, \( AA(t) \), can be modeled by the equation: \[ AA(t) = 33 - 2t \]
Snowman B:
- Initial height: 53 inches
- Decrease rate: 6 inches per hour
The height of Snowman B, \( BB(t) \), can be modeled by the equation: \[ BB(t) = 53 - 6t \]
To find the interval of time when Snowman A is taller than Snowman B, we want to solve the inequality: \[ AA(t) > BB(t) \]
Substituting in the equations for \( AA(t) \) and \( BB(t) \): \[ 33 - 2t > 53 - 6t \]
Now, let's solve for \( t \):
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Add \( 6t \) to both sides: \[ 33 + 4t > 53 \]
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Subtract 33 from both sides: \[ 4t > 20 \]
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Divide both sides by 4: \[ t > 5 \]
Now, we need to check when Snowman A becomes shorter than or equal to Snowman B:
Using the same equations: Set \( AA(t) \leq BB(t) \): \[ 33 - 2t \leq 53 - 6t \]
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Add \( 6t \) to both sides: \[ 33 + 4t \leq 53 \]
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Subtract 33 from both sides: \[ 4t \leq 20 \]
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Divide both sides by 4: \[ t \leq 5 \]
Therefore, combining these results, we find:
- Snowman A is taller than Snowman B when \( t > 5 \) hours.
- Snowman A is shorter than or equal to Snowman B when \( t \leq 5 \) hours.
Summary:
- The height of Snowman A is greater than that of Snowman B for \( t > 5 \) hours after sunrise.