On a piece of paper graph
f(x) = {-1 if -1 <= x < 0}
{ -2 if 0 <= x < 0}
{ -3 if 1 <= x < 2
then determine which answer choice matches the graph you drew
5 answers
Without a specific graph provided, I cannot determine which answer choice matches the graph you drew. Please provide the options for me to compare them and identify the correct match.
these are the four graphs
Line 1 open circle endpoint is at (negative 1, 1) and closed circle endpoint at (0, 1) on Y-axis. Line 2 open circle endpoint is at (0, 2) on Y-axis and closed circle endpoint at (1, 2) in quadrant 1. Line 3 open circle endpoint is at (1, 3) and closed circle endpoint at (2, 3 ). The lines move one unit upward towards right.
Line 1 open circle endpoint is at (negative 2, negative 3) and closed circle endpoint at (negative 1, negative 3) in quadrant 3. Line 2 open circle endpoint is at (negative 1, negative 2) in quadrant 3 and closed circle endpoint at (0, negative 2) on Y-axis. Line 3 open circle endpoint is at (0, negative 1) on Y-axis and closed circle endpoint at (1, negative 1) in quadrant 4. The lines move one unit upward towards right.
Line 1 closed circle endpoint is at (0, 1) and open circle endpoint is at (1, 1). Line 2 closed circle endpoint is at (1, 2) and open circle endpoint is at (2, 2). Line 3 closed circle endpoint is at (2, 3) and open circle endpoint is at (3,3 ). The lines move one unit upward towards right in quadrant 1.
Line 1 closed circle endpoint is at (negative 1, negative 1) in quadrant 3 and open circle endpoint is at (0, negative 1) on Y-axis. Line 2 closed circle endpoint is at (0, negative 2) Y-axis and open circle endpoint is at (1, negative 2) in quadrant 4. Line 3 closed circle endpoint is at (1, negative 3) and open circle endpoint is at (2, negative 3) in quadrant 4. The lines move one unit downward toward right.
Line 1 open circle endpoint is at (negative 1, 1) and closed circle endpoint at (0, 1) on Y-axis. Line 2 open circle endpoint is at (0, 2) on Y-axis and closed circle endpoint at (1, 2) in quadrant 1. Line 3 open circle endpoint is at (1, 3) and closed circle endpoint at (2, 3 ). The lines move one unit upward towards right.
Line 1 open circle endpoint is at (negative 2, negative 3) and closed circle endpoint at (negative 1, negative 3) in quadrant 3. Line 2 open circle endpoint is at (negative 1, negative 2) in quadrant 3 and closed circle endpoint at (0, negative 2) on Y-axis. Line 3 open circle endpoint is at (0, negative 1) on Y-axis and closed circle endpoint at (1, negative 1) in quadrant 4. The lines move one unit upward towards right.
Line 1 closed circle endpoint is at (0, 1) and open circle endpoint is at (1, 1). Line 2 closed circle endpoint is at (1, 2) and open circle endpoint is at (2, 2). Line 3 closed circle endpoint is at (2, 3) and open circle endpoint is at (3,3 ). The lines move one unit upward towards right in quadrant 1.
Line 1 closed circle endpoint is at (negative 1, negative 1) in quadrant 3 and open circle endpoint is at (0, negative 1) on Y-axis. Line 2 closed circle endpoint is at (0, negative 2) Y-axis and open circle endpoint is at (1, negative 2) in quadrant 4. Line 3 closed circle endpoint is at (1, negative 3) and open circle endpoint is at (2, negative 3) in quadrant 4. The lines move one unit downward toward right.
Based on the description provided, the graph that matches the function f(x) = {-1 if -1 <= x < 0}, { -2 if 0 <= x < 0}, { -3 if 1 <= x < 2 would be:
Line 1 closed circle endpoint is at (0, 1) and open circle endpoint is at (1, 1).
Line 2 closed circle endpoint is at (1, 2) and open circle endpoint is at (2, 2).
Line 3 closed circle endpoint is at (2, 3) and open circle endpoint is at (3,3).
This matches the given function where values are -1, -2, and -3 at specific intervals.
Line 1 closed circle endpoint is at (0, 1) and open circle endpoint is at (1, 1).
Line 2 closed circle endpoint is at (1, 2) and open circle endpoint is at (2, 2).
Line 3 closed circle endpoint is at (2, 3) and open circle endpoint is at (3,3).
This matches the given function where values are -1, -2, and -3 at specific intervals.
which graph is correct
The correct graph based on the function f(x) = {-1 if -1 <= x < 0}, { -2 if 0 <= x < 0}, { -3 if 1 <= x < 2 is:
Line 1 closed circle endpoint is at (0, 1) and open circle endpoint is at (1, 1).
Line 2 closed circle endpoint is at (1, 2) and open circle endpoint is at (2, 2).
Line 3 closed circle endpoint is at (2, 3) and open circle endpoint is at (3,3).
This represents the function accurately with the given values at specific intervals.
Line 1 closed circle endpoint is at (0, 1) and open circle endpoint is at (1, 1).
Line 2 closed circle endpoint is at (1, 2) and open circle endpoint is at (2, 2).
Line 3 closed circle endpoint is at (2, 3) and open circle endpoint is at (3,3).
This represents the function accurately with the given values at specific intervals.
1 answer