Asked by Charles
On a part-time job, you are asked to bring a cylindrical iron rod of length 91.9 cm and diameter 2.70 cm from a storage room to a machinist. Calculate the weight of the rod, w.
Answers
Answered by
drwls
The volume of the rod is
V = pi*(D^2/4)*L = 526 cm^3
Multiply that by the density of iron for the mass. The density is 7.86 g/cm^3.
M = 4140 g = 4.14 kg (about 9.11 pounds)
Multiply Mass (in kg) by g = 9.8 m/s^2 if you want the weight in Newtons.
V = pi*(D^2/4)*L = 526 cm^3
Multiply that by the density of iron for the mass. The density is 7.86 g/cm^3.
M = 4140 g = 4.14 kg (about 9.11 pounds)
Multiply Mass (in kg) by g = 9.8 m/s^2 if you want the weight in Newtons.
Answered by
smith joseph
A beaker of water rests on an electronic balance that reads 975.0 g. A 2.0 cm diameter solid gold copper ball attached to a string is submerged in the water, but does not touch the bottom. What's the tension in the string? What's the new balance reading?
Please, help me.
Please, help me.
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