On a hot summer day, a young girl swings on a rope above the local swimming hole. When she lets go of the rope her initial velocity is 2.25 m/s at an angle of 35 degrees above the horizontal. If she is in flight for 0.616 s, how high above the water was she when she let go of the rope?
3 answers
Your name changes on each post. Are you answer grazing? Appears so. Never trust a person who changes their name on each question.
= 5.65m.
There are a whole mess of these questions all basically the same this morning. Read any old answer.
u = speed * cos angle
Vi = speed * sin angle
v = Vi - 9.81 t
v = 0 at top
h = Hi + Vi t - 4.9 t^2
https://www.mathsisfun.com/quadratic-equation-solver.html
range = u t
u = speed * cos angle
Vi = speed * sin angle
v = Vi - 9.81 t
v = 0 at top
h = Hi + Vi t - 4.9 t^2
https://www.mathsisfun.com/quadratic-equation-solver.html
range = u t
3 answers