To find which point lies on a side of the pre-image square \( RSTU \) with vertices \( R(-8, 1) \), \( S(-4, 1) \), \( T(-4, -3) \), and \( U(-8, -3) \), we first need to identify the coordinates of the sides of the square.
The sides of the square are as follows:
-
From \( R(-8, 1) \) to \( S(-4, 1) \): This side is horizontal at \( y = 1 \) between \( x = -8 \) and \( x = -4 \).
-
From \( S(-4, 1) \) to \( T(-4, -3) \): This side is vertical at \( x = -4 \) between \( y = 1 \) and \( y = -3 \).
-
From \( T(-4, -3) \) to \( U(-8, -3) \): This side is horizontal at \( y = -3 \) between \( x = -4 \) and \( x = -8 \).
-
From \( U(-8, -3) \) to \( R(-8, 1) \): This side is vertical at \( x = -8 \) between \( y = -3 \) and \( y = 1 \).
Now, we need to check the possible coordinates given in the options to see which point lies on one of these sides:
-
Point: \( (-5, -3) \)
- This point is not on the side since \( x = -5 \) is not in the range of \( x = -8 \) and \( x = -4 \) for \( y = -3 \).
-
Point: \( (3, -3) \)
- This point is also not on the side since \( x = 3 \) is not in the range of \( x = -8 \) and \( x = -4 \) for \( y = -3 \).
-
Point: \( (-1, -6) \)
- This point is not on the side since \( y = -6 \) is not in the range of \( y = -3 \) and \( y = 1 \).
-
Point: \( (4, -9) \)
- This point is not on the side since \( x = 4 \) is also not in the range of \( x = -8 \) and \( x = -4 \).
None of the points listed are on the sides of the square \( RSTU \). Is there any mistake in the provided options, or would more information be helpful?