To determine which point is a solution to the inequality \( y > -3x + 2 \), we can evaluate each point to see if they satisfy the inequality.
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Point (0, 2): \[ y > -3(0) + 2 \Rightarrow 2 > 2 \quad \text{(false)} \]
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Point (2, 0): \[ y > -3(2) + 2 \Rightarrow 0 > -6 + 2 \Rightarrow 0 > -4 \quad \text{(true)} \]
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Point (1, -2): \[ y > -3(1) + 2 \Rightarrow -2 > -3 + 2 \Rightarrow -2 > -1 \quad \text{(false)} \]
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Point (-2, 1): \[ y > -3(-2) + 2 \Rightarrow 1 > 6 + 2 \Rightarrow 1 > 8 \quad \text{(false)} \]
From the evaluations, the only point that satisfies the inequality \( y > -3x + 2 \) is:
(2, 0).