To identify which interval for the graphed function has a local minimum of \(0\), we need to examine the given points and their significance on the function. Specifically, we are given the following details:
- Minimum values at \((-1.56, -6)\) and \((3, 0)\)
- Maximum value at \((1.2, 2.9)\)
- The function crosses the x-axis at \((-2.5, 0)\), \((0, 0)\), and \((3, 0)\)
- The function crosses the y-axis at \((0, 0)\)
From this information, the points where the function crosses the x-axis indicate that the function value is zero at these points. Since the point \((3, 0)\) is specified as a minimum value, it is a local minimum value of 0.
Given the intervals:
\[ [-3, -2] \]
\[ [-2, 0] \]
\[ [1, 2] \]
\[ [2, 4] \]
We examine where \( x = 3 \) lies. The interval that includes \( x = 3 \) is \([2, 4]\).
Hence, the interval for the graphed function that has a local minimum of \(0\) is:
\[ [2, 4] \]
On a coordinate plane, a curved line with minimum values of (negative 1.56, negative 6) and (3, 0), and a maximum value of (1.2, 2.9), crosses the x-axis at (negative 2.5, 0), (0, 0), and (3, 0), and crosses the y-axis at (0, 0).
Which interval for the graphed function has a local minimum of 0?
[–3, –2]
[–2, 0]
[1, 2]
[2, 4]
1 answer
1 answer