To determine which interval contains the local maximum for the given function, let's focus on the provided piece of information about the maximum value and the intervals.
According to the information provided:
- The local maximum occurs at the point \((1.55, 10.8)\).
Now, we need to identify within which of the given intervals this \(x\)-value lies:
- \([-3, -2]\): This interval ranges from \(x = -3\) to \(x = -2\). Since \(1.55\) is not between \(-3\) and \(-2\), this interval does not contain the local maximum.
- \([-2, 0]\): This interval ranges from \(x = -2\) to \(x = 0\). Since \(1.55\) is not between \(-2\) and \(0\), this interval does not contain the local maximum.
- \([0, 2]\): This interval ranges from \(x = 0\) to \(x = 2\). Since \(1.55\) is within this interval, this interval contains the local maximum.
- \([2, 4]\): This interval ranges from \(x = 2\) to \(x = 4\). Since \(1.55\) is not between \(2\) and \(4\), this interval does not contain the local maximum.
Thus, the interval \([0, 2]\) contains the local maximum of the graphed function.
On a coordinate plane, a curved line with minimum values of (negative 0.8, negative 2.8) and (3, 0), and a maximum value of (1.55, 10.8), crosses the x-axis at (negative 2.5, 0), (0, 0), and (3, 0), and crosses the y-axis at (0, 0).
Which interval for the graphed function contains the local maximum?
[–3, –2]
[–2, 0]
[0, 2]
[2, 4]
1 answer
1 answer