First, we need to calculate the surface area of the cylinder to determine how much wrapping paper Olga will need.
The formula for the surface area of a cylinder is:
Surface Area = 2πr(r+h)
Given that the diameter is 6 inches, the radius (r) would be half of that, so r = 6/2 = 3 inches.
Now we can plug in the values:
Surface Area = 2 * 3.14 * 3(3 + 12)
Surface Area = 2 * 3.14 * 3(15)
Surface Area = 2 * 3.14 * 45
Surface Area = 282.6 inches^2
Therefore, Olga will need 282.6 square inches of wrapping paper for each gift she wraps.
Olga is making presents for her teachers and needs to wrap them. She places the gifts in a right circular cylinder with a height of 12 inches and diameter of 6 inches. How much wrapping paper does she need for each gift she is going to wrap? Use 3.14 for π .(1 point)
inches^2
3 answers
UMM
I'll make the correction. The formula for the surface area of a cylinder is:
Surface Area = 2πr(r+h) + 2πr^2
Given that the diameter is 6 inches, the radius (r) would be half of that, so r = 6/2 = 3 inches.
Now we can plug in the values:
Surface Area = 2 * 3.14 * 3(3 + 12) + 2 * 3.14 * 3^2
Surface Area = 2 * 3.14 * 3(15) + 2 * 3.14 * 9
Surface Area = 2 * 3.14 * 45 + 2 * 3.14 * 9
Surface Area = 282.6 + 56.52
Surface Area = 339.12 inches^2
Therefore, Olga will need 339.12 square inches of wrapping paper for each gift she wraps.
Surface Area = 2πr(r+h) + 2πr^2
Given that the diameter is 6 inches, the radius (r) would be half of that, so r = 6/2 = 3 inches.
Now we can plug in the values:
Surface Area = 2 * 3.14 * 3(3 + 12) + 2 * 3.14 * 3^2
Surface Area = 2 * 3.14 * 3(15) + 2 * 3.14 * 9
Surface Area = 2 * 3.14 * 45 + 2 * 3.14 * 9
Surface Area = 282.6 + 56.52
Surface Area = 339.12 inches^2
Therefore, Olga will need 339.12 square inches of wrapping paper for each gift she wraps.