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Old coordinates:A=(5,-1) B=(5,-9) C=(2,-7)

B) Now reflect △A across the y-axis to create. What are the new coordinates? (3 points)
′B′C′ △A " B " C "

3 answers

To reflect the triangle \( \triangle ABC \) across the y-axis, we need to change the sign of the x-coordinates of each vertex, while keeping the y-coordinates the same.

Given the vertices:

  • \( A = (5, -1) \)
  • \( B = (5, -9) \)
  • \( C = (2, -7) \)

The reflected vertices will be:

  • \( A' = (-5, -1) \)
  • \( B' = (-5, -9) \)
  • \( C' = (-2, -7) \)

So the new coordinates after reflecting across the y-axis are:

  • \( A' = (-5, -1) \)
  • \( B' = (-5, -9) \)
  • \( C' = (-2, -7) \)

Thus, the new triangle \( \triangle A'B'C' \) has the coordinates:

  • \( A'(-5, -1) \)
  • \( B'(-5, -9) \)
  • \( C'(-2, -7) \)
wrong

I apologize for the confusion in my previous response. Let's correctly reflect the triangle \( \triangle ABC \) across the y-axis step by step.

Reflecting across the y-axis involves changing the signs of the x-coordinates of each point.

Given the original coordinates:

  • \( A = (5, -1) \)
  • \( B = (5, -9) \)
  • \( C = (2, -7) \)

Now, we'll reflect each point across the y-axis:

  1. For point \( A \):

    • Reflect \( (5, -1) \) → \( A' = (-5, -1) \)

  2. For point \( B \):

    • Reflect \( (5, -9) \) → \( B' = (-5, -9) \)

  3. For point \( C \):

    • Reflect \( (2, -7) \) → \( C' = (-2, -7) \)

Thus, the new coordinates after reflection across the y-axis are:

  • \( A' = (-5, -1) \)
  • \( B' = (-5, -9) \)
  • \( C' = (-2, -7) \)

The reflected triangle \( \triangle A'B'C' \) consists of the points:

  • \( A'(-5, -1) \)
  • \( B'(-5, -9) \)
  • \( C'(-2, -7) \)

If there’s a specific point where you believe the mistake occurred or if you need additional clarification, please let me know!