You must have a table or a graph or something like that which will tell you the number of grams of NaI in a saturated solution. From the data you should get something like grams/mL or grams/L. Whatever you get change that to grams/L then convert grams to mols.
mols = grams NaI/molar mass NaI
Okay so the question is: what would be the molarity of a saturated aqueous solution of NaI prepared at 25 C, assuming that the added NaI does not add significantly to the volume of the water?
My question is, I got confused on what formula I use to for the question, because the formula for Molarity is (M=#of moles/# of L), but it doesn't give me that.
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