V=d/t
d=V*t
Let t be the time the man is jogging. t-2 is the time the dog is running (since the dog waits 2s). When they catch up with each other displacement will be equal.
(4m/s)(t-2)=(1.8m/s)(t)
Okay, I have an example problem that I'm trying to solve that comes with the answer; I'm just trying to figure out what to do.
A man jogs at a speed of 1.8 m/s. His dog
waits 2 s and then takes off running at a speed
of 4 m/s to catch the man.
How far will they have each traveled when
the dog catches up with the man?
Correct answer: 6.54545 m.
I think that I'll need to set the two equations equal and that I see that I'm given time and two sets of constant velocity but I looked at all my equations that I have and I can't figure out what equation I need.
Any help would be welcome.
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