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Ok so you're supposed to solve the system by method of substitution. And the problem is:

-2/3x + y = 2
2x - 3y = 6
So i put y= 2/3x into the second equation which looks like:
2x - 3(2/3x + 2) = 6
and then
2x-2x-6=6
So like everything cancels out? So then what do you put as the answer??
Thanks!

3 answers

so i think its
x=0
then solver y
2(0)-3y=6
y=-2
oh, ok thanks!
welcome
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