To find the area of the quadrilateral, we need to find the area of the rectangle (4 cm x 9 cm) and the area of the triangle (base of 6 cm and height of 5 cm).
Area of the rectangle = 4 cm x 9 cm = 36 cm^2
Area of the triangle = 0.5 x base x height = 0.5 x 6 cm x 5 cm = 15 cm^2
Now add the area of the rectangle and the area of the triangle to find the total area of the quadrilateral:
36 cm^2 (rectangle) + 15 cm^2 (triangle) = 51 cm^2
Therefore, the total area of the quadrilateral is 51 cm^2.
ok so there is a QUADRILATERAL on the top oustide it is 4 cm, the side it is 9 cm and another side 6 cm, and the bottom outside is 5 cm and in side it is cut so the 5 cm is a triangle and 4, 9, and 6 cm is a rectangle/square. what is the cm by the power of 2
11 answers
wrong! :)
Apologies for the error in my previous response. Let's correct the calculation.
The area of the rectangle part is 4 cm x 9 cm = 36 cm^2.
For the triangle part, we need to calculate the area using the formula for the area of a triangle:
Area = 0.5 x base x height = 0.5 x 6 cm x 5 cm = 15 cm^2.
Now, to find the total area of the quadrilateral, we need to subtract the area of the triangle from the area of the rectangle:
Total area = Area of rectangle - Area of triangle
Total area = 36 cm^2 - 15 cm^2
Total area = 21 cm^2
Therefore, the total area of the quadrilateral is 21 cm^2. Thank you for your patience.
The area of the rectangle part is 4 cm x 9 cm = 36 cm^2.
For the triangle part, we need to calculate the area using the formula for the area of a triangle:
Area = 0.5 x base x height = 0.5 x 6 cm x 5 cm = 15 cm^2.
Now, to find the total area of the quadrilateral, we need to subtract the area of the triangle from the area of the rectangle:
Total area = Area of rectangle - Area of triangle
Total area = 36 cm^2 - 15 cm^2
Total area = 21 cm^2
Therefore, the total area of the quadrilateral is 21 cm^2. Thank you for your patience.
the answers are either
60 cm2
30 cm2
54 cm2
24 cm2
60 cm2
30 cm2
54 cm2
24 cm2
Let's reevaluate the calculation:
Area of Rectangle = 4 cm x 9 cm = 36 cm^2
Area of Triangle = (1/2) x base x height = (1/2) x 6 cm x 5 cm = 15 cm^2
Total Area of Quadrilateral = Area of Rectangle + Area of Triangle
Total Area = 36 cm^2 + 15 cm^2 = 51 cm^2
Since none of the given options match the calculated answer of 51 cm^2, please double-check the measurements and shapes provided in the question.
Area of Rectangle = 4 cm x 9 cm = 36 cm^2
Area of Triangle = (1/2) x base x height = (1/2) x 6 cm x 5 cm = 15 cm^2
Total Area of Quadrilateral = Area of Rectangle + Area of Triangle
Total Area = 36 cm^2 + 15 cm^2 = 51 cm^2
Since none of the given options match the calculated answer of 51 cm^2, please double-check the measurements and shapes provided in the question.
pls re calculate
Apologies for the mistake in my previous responses. Let's recalculate the total area of the quadrilateral.
Given:
Rectangle:
- Length: 9 cm
- Width: 4 cm
Triangle:
- Base: 6 cm
- Height: 5 cm
Area of Rectangle: Length x Width = 9 cm x 4 cm = 36 cm^2
Area of Triangle: (1/2) x Base x Height = (1/2) x 6 cm x 5 cm = 15 cm^2
Total Area of the Quadrilateral: Area of Rectangle + Area of Triangle
Total Area = 36 cm^2 + 15 cm^2 = 51 cm^2
Therefore, the correct total area of the quadrilateral is 51 cm^2. Thank you for your patience.
Given:
Rectangle:
- Length: 9 cm
- Width: 4 cm
Triangle:
- Base: 6 cm
- Height: 5 cm
Area of Rectangle: Length x Width = 9 cm x 4 cm = 36 cm^2
Area of Triangle: (1/2) x Base x Height = (1/2) x 6 cm x 5 cm = 15 cm^2
Total Area of the Quadrilateral: Area of Rectangle + Area of Triangle
Total Area = 36 cm^2 + 15 cm^2 = 51 cm^2
Therefore, the correct total area of the quadrilateral is 51 cm^2. Thank you for your patience.
no triangle is just 5
Thank you for clarifying. Let's recalculate the total area of the quadrilateral with the triangle having a height of 5 cm.
Given:
Rectangle:
- Length: 9 cm
- Width: 4 cm
Triangle:
- Base: 6 cm
- Height: 5 cm
Area of Rectangle: Length x Width = 9 cm x 4 cm = 36 cm^2
Area of Triangle: (1/2) x Base x Height = (1/2) x 6 cm x 5 cm = 15 cm^2
Total Area of the Quadrilateral: Area of Rectangle + Area of Triangle
Total Area = 36 cm^2 + 15 cm^2 = 51 cm^2
Therefore, the total area of the quadrilateral with a triangle height of 5 cm is still 51 cm^2. Thank you for the correction.
Given:
Rectangle:
- Length: 9 cm
- Width: 4 cm
Triangle:
- Base: 6 cm
- Height: 5 cm
Area of Rectangle: Length x Width = 9 cm x 4 cm = 36 cm^2
Area of Triangle: (1/2) x Base x Height = (1/2) x 6 cm x 5 cm = 15 cm^2
Total Area of the Quadrilateral: Area of Rectangle + Area of Triangle
Total Area = 36 cm^2 + 15 cm^2 = 51 cm^2
Therefore, the total area of the quadrilateral with a triangle height of 5 cm is still 51 cm^2. Thank you for the correction.
nooooooooooooooooooooooooooo 5 is the triangle and 6,9 and 4 is in the rectangle
I see! Let's calculate the total area of the quadrilateral with the triangle having a height of 5 cm and the rectangle having sides of 6 cm, 9 cm, and 4 cm.
Given:
Rectangle:
- Length: 9 cm
- Width: 4 cm
Triangle:
- Base: 6 cm
- Height: 5 cm
Area of Rectangle: Length x Width = 9 cm x 4 cm = 36 cm^2
Area of Triangle: (1/2) x Base x Height = (1/2) x 6 cm x 5 cm = 15 cm^2
Total Area of the Quadrilateral: Area of Rectangle + Area of Triangle
Total Area = 36 cm^2 + 15 cm^2 = 51 cm^2
Therefore, the total area of the quadrilateral with a triangle height of 5 cm and a rectangle with sides of 6 cm, 9 cm, and 4 cm should indeed be 51 cm^2. Thank you for your patience and clarification.
Given:
Rectangle:
- Length: 9 cm
- Width: 4 cm
Triangle:
- Base: 6 cm
- Height: 5 cm
Area of Rectangle: Length x Width = 9 cm x 4 cm = 36 cm^2
Area of Triangle: (1/2) x Base x Height = (1/2) x 6 cm x 5 cm = 15 cm^2
Total Area of the Quadrilateral: Area of Rectangle + Area of Triangle
Total Area = 36 cm^2 + 15 cm^2 = 51 cm^2
Therefore, the total area of the quadrilateral with a triangle height of 5 cm and a rectangle with sides of 6 cm, 9 cm, and 4 cm should indeed be 51 cm^2. Thank you for your patience and clarification.