Asked by Blaine

ok im tring to find the slope intercept form of a perpindicular line so i can graph it heres the equation: (-3,1) y=-3x+7
Answered by drwls
It makes no sense to put a pair of coordinates (-3, 1) in front of a "y" term in an equation. Are you trying to find the equatin of a line that passes through (-3,1) and is perpendicular to
y = -3x+7 ?

That would not make sense either, becasuse y = -3x +7 does not pass through that point.
Answered by Reiny
Is your new line perpendicular to y = -3x + 7 ?

If so, then the new slope must be (+1/3) and the new line is
y = (1/3)x + b
but (-3,1) is supposed to be on this new line, so
1 = (1/3)(-3) + b
1 = -1 + b
b = 2

new line : y = (1/3)x + 2
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