Ok feeling kinda dumb because this isn't coming out right. I know it's simple.

Question

log6 (x -3) + log6(x -6) - log6(x + 1) = 2

Answer 1

adding logs is multiplying arguments

log 6 [(x-3)(x-6)(x+1)] = 2

6^log 6 [(x-3)(x-6)(x+1)] = 6^2 = 36

x^3 - 8 x^2 + 9 x + 18 = 36

x^3 - 8 x^2 + 9 x - 18 = 0

I do not see any easy factors. Have to solve by iteration.