Oil from a ruptured tanker spreads in a circular pattern. If the radius of the circle increases at the constant rate of 1.5 feet per second, how fast is the enclosed area increasing at the end of 2 hours?

Answer 1

A=πr²

dr/dt=1.5 ft/s
r=1.5t
dA/dt = dA/dr * dr/dt
=2πr * 1.5 sq.ft/s
=3πr
=3π(1.5*2*3600)
=28800π sq.ft/s

Answer 2

Oil spills out of a tanker at rate of 50ft3 per minute. The oil spreads in a 3
circle with thickness of 1 ft. Determine the rate at which the radius of the oil is increasing 48
when the radius reaches 200 ft.

Answer 3

But it's 10 mins instead of two hr

Answer 4

They reuse the questions from ur generation??? Bruhhh my generation is messed up . Hs class of 293456677