If the three numbers are x,y,z, then we know that
y = 2x
y = 3z
(x+y+z)/3 = 44
Now just find z.
Of three numbers, second is twice the first and is also thrice the third. If the average of three numbers is 44, find the largest.
4 answers
pl explain how can we find z. what is the answer.
clear the fraction, and you have
x+y+z = 3*44 = 132
Now, since y=2x=3z,
2x=3z, and x = 3z/2
Now just add them up and you have
3z/2 + 3z + z = 132
11z/2 = 132
z = 132 * 2/11 = 24
x+y+z = 3*44 = 132
Now, since y=2x=3z,
2x=3z, and x = 3z/2
Now just add them up and you have
3z/2 + 3z + z = 132
11z/2 = 132
z = 132 * 2/11 = 24
Thank u sir.