Of the parts produced by a particular machine, 1.5% are defective. If a random sample of 11 parts produced by this machine contains 2 or more defective parts, the machine is shut down for repairs. Find the probability that the machine will be shut down for repairs based on this sampling plan.

Answer 1

1-p(x = 0) + p(x = 1)

1-[(11C0)(.015)^0(.985)^11 + 11C1 *0.015^1 *.985^10)]

1-[.84684 + .14185]
1-.9887 = 0.0113