I'm not 100% sure, but I believe that it is dealing with the electronegativity. to determine the type of bond a molecule has, you use the electronegativity. You take the higher electronegativity and subtract the lower electronegativity. if the value is less than 0.4, the bond is non-polar covalent bonding (there is no charge for either atom), if 0.4-1.7 it is polar covalent bonding (partial ionic charge for each atom), and if greater than 1.7, it is ionic (in a binary molecule one atom becomes a cation and the other becomes an anion.) The greater this value, it should require more energy to remove. So in this case, the answer should be B because Sulfur's electronegativity is 2.58 and Potassium is 0.82 (I'm pretty certain that the amount of the atom doesn't matter in the equation) this ends up as 1.76, which is the lowest of all the compounds listed.
I'll come back on tomorrow to correct any mistakes I stated.
Sorry if I'm wrong
Of the compounds below,_____ has the smallest ionic separation and why?
A.RbF
B.K2S
C.SrBr2
D.KF
E.RbCl
--> How does one determine if a compound has a high or low ionic separation, and what is ionic separation?
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